Given the following equation, N₂O(g)+ NO₂(g)→ 3 NO(g)ΔG°_rxn = -23.0 kJ Calculate ΔG°_rxn for the following reaction. 18 NO(g)→ 6 N₂O(g)+ 6 NO₂(g)

Name: Given the following equation, N 2 O(g)+ NO 2 (g)→ 3 NO(g)ΔG° rxn = -23.0 kJ Calculate ΔG° rxn for the following reaction. 18 NO(g)→ 6 N 2 O(g)+ 6 NO 2 (g)
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Question

Quizplus · Accepted Answer

The given reaction is the reverse of the original reaction multiplied by 6. Therefore, ΔG° for the reverse reaction is +23.0 kJ, and multiplying by 6 gives 138 kJ.

Given the Following Equation, N2O(g)+ NO2(g)→ 3 NO(g)ΔG°rxn = -23

Given the Following Equation, N₂O(g)+ NO₂(g)→ 3 NO(g)ΔG°_rxn = -23