Use the tabulated half-cell potentials to calculate ΔG° for the following balanced redox reaction. Pb²⁺(aq)+ Cu(s)→ Pb(s)+ Cu²⁺(aq) A) -41 kJ B) -0.47 kJ C) +46 kJ D) +91 kJ E) -21 kJ

Question

Quizplus · Accepted Answer

The standard cell potential (E°) for the reaction can be calculated using the standard reduction potentials: E°(Cu²⁺/Cu) = +0.34 V and E°(Pb²⁺/Pb) = -0.13 V. The cell potential is E°cell = E°(Cu²⁺/Cu) - E°(Pb²⁺/Pb) = 0.34 V - (-0.13 V) = 0.47 V. ΔG° = -nFE°cell, where n = 2 (moles of electrons transferred) and F = 96485 C/mol. ΔG° = -2 * 96485 * 0.47 = -90589 J = -91 kJ.

Use the Tabulated Half-Cell Potentials to Calculate ΔG° for the Following