Balance the following reaction in KOH.What are the coefficients in front of C9H20O2 and KMnO4 in the balanced reaction? C9H20O2(aq) + KMnO4(aq) → C9H14O4K2(aq) + MnO2(aq)
A) C9H20O2 = 3, KMnO4 = 8
B) C9H20O2 = 3, KMnO4 = 4
C) C9H20O2 = 8, KMnO4 = 4
D) C9H20O2 = 2, KMnO4 = 8
E) C9H20O2 = 3, KMnO4 = 2
Correct Answer:
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