Balance the following reaction in KOH.What are the coefficients in front of H2O and KOH in the balanced reaction and list which side of the equation that H2O and KOH appear? C10H22O2(aq) + KMnO4(aq) → C10H16O4K2(aq) + MnO2(aq)
A) H2O = 1, KOH = 4, left
B) H2O = 4, KOH = 1, left
C) H2O = 8, KOH = 2, right
D) H2O = 3, KOH = 2, right
E) H2O = 4, KOH = 2, left
Correct Answer:
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