The half-life of cobalt-60 is 5.20 yr.How many milligrams of a 2.000-mg sample remain after 6.55 years?

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The amount of a radioactive substance that remains after a certain period can be calculated using the formula: $A = A_0 \times (1/2)^{t/T}$, where $A$ is the amount remaining, $A_0$ is the initial amount, $t$ is the time elapsed, and $T$ is the half-life of the substance. For cobalt-60, with $A_0 = 2.000$ mg, $t = 6.55$ years, and $T = 5.20$ years, the calculation is $2.000 \times (1/2)^{6.55/5.20} \approx 0.837$ mg.

The Half-Life of Cobalt-60 Is 5