What is the oxidation number of oxygen in H₂O₂?

Question

Quizplus · Accepted Answer

In this compound, hydrogen has an oxidation state of +1, sulfur has an oxidation state of either +2 or -2, and since the compound is neutral, the sum of the oxidation states of all the atoms must be zero. Therefore, we can calculate the oxidation state of oxygen as follows:
(+1) + x + 2(-2) + (-1) + x + 2(-2) + (-1) + 2x + 2(-2) = 0
Simplifying this expression, we get:
4x - 12 = 0
x = +3
Therefore, the oxidation state of oxygen in this compound is -1. The correct answer is D.

What Is the Oxidation Number of Oxygen in H2O2

What Is the Oxidation Number of Oxygen in H₂O₂