Why Does the Following Code Cause a Compiler Error? Try

Why does the following code cause a compiler error? try
{
Number = Integer.parseInt(str) ;
}
Catch (IllegalArgumentException e)
{
System.out.println("Bad number format.") ;
}
Catch (NumberFormatException e)
{
System.out.println(str + " is not a number.") ;
}

A) Because you can have only one catch clause in a try statement.
B) Because NumberFormatException inherits from IllegalArgumentException.The code should handle NumberFormatException before IllegalArgumentException.
C) Because the Integer.parseInt method does not throw a NumberFormatException.
D) Because the Integer.parseInt method does not throw an IllegalArgumentException.