A Sweet Pea Plant of Genotype A/A

A sweet pea plant of genotype A/A ^. B/B is crossed to one that is a/a ^. b/b to produce a dihybrid F₁.One cell of one F₁ individual (genotype A/a ^. B/b) goes through meiosis and produces four gametes of the following genotypes: A ^. b,A ^. b,a ^.B and a ^.B.What can be concluded regarding the linkage relationship between the two genes?

A) Genes A and B are linked;the result is indicative of linkage as the gametes are recombinants.
B) Genes A and B are linked;the result is indicative of linkage as the gametes are the products of crossovers.
C) Genes A and B could be linked or unlinked;the result is not indicative of either,because in both cases it's possible to obtain 100% recombinant gametes from one meiosis.
D) Genes A and B could be linked or unlinked;the result is unusual as we should never obtain more than 50% recombinants from one meiosis.
E) Genes A and B are unlinked;the result is indicative of independent assortment as only two genotypes are represented among the gametes.