In an experiment carried out in a chicken population,measurements of fat content reveal that the genetic variance for this trait is 120 g²,the environmental variance is 80 g² and the variance due to dominance is 38 g².The narrow-sense heritability (h²)of fat content in these chickens is: A)0.24. B)0.41. C)0.52. D)0.74. E)0.90 .

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Quizplus · Accepted Answer

Narrow-sense heritability (h^2) is calculated as the ratio of additive genetic variance (V_A) to the total phenotypic variance (V_P). The total phenotypic variance is the sum of genetic variance (V_G), environmental variance (V_E), and variance due to dominance (V_D). In this case, V_G is given as 120, V_E as 80, and V_D as 38. However, for narrow-sense heritability, we only consider additive genetic variance (V_A) and not the variance due to dominance. Therefore, V_A = V_G - V_D = 120 - 38 = 82. The total phenotypic variance V_P = V_G + V_E = 120 + 80 = 200. Thus, h^2 = V_A / V_P = 82 / 200 = 0.41.

In an Experiment Carried Out in a Chicken Population,measurements of Fat