Silver chloride (AgCl)is relatively insoluble in water.At 25$^{\circ}$C, 1.3 $\times$ 10³ L of water is needed to dissolve 2.5 g of AgCl.What mass (in milligrams)of AgCl will dissolve in 1.0 L of water? A) 1.9 $\times$ 10^-3 mg B) 1.9 mg C) 0.52 mg D) 520 mg E) 1.9 $\times$ 10^-6 mg

Question

Quizplus · Accepted Answer

To find the mass of AgCl that will dissolve in 1.0 L of water, we use the given ratio: 2.5 g of AgCl dissolves in 1.3 $\times$ 10³ L of water. Therefore, in 1.0 L of water, the mass of AgCl that will dissolve is (2.5 g / 1.3 $\times$ 10³ L) $\times$ 1.0 L = 0.0019 g = 1.9 mg.

Silver Chloride (AgCl)is Relatively Insoluble in Water ∘^{\circ}∘ C, 13 ×\times× 103 L of Water Is Needed to Dissolve 2

Silver Chloride (AgCl)is Relatively Insoluble in Water $^{\circ}$ C, 13 $\times$ 10³ L of Water Is Needed to Dissolve 2