Calcium carbonate,or limestone,is relatively insoluble in water.At 25$^{\circ}$C,only 5.8 mg will dissolve in 1.0 liter of water.What volume of water is needed to dissolve 5.0 g of calcium carbonate? A) 4.6 $\times$ 10^-3 L B) 3.0 $\times$ 10^-2 L C) 1.4 $\times$ 10² L D) 3.4 $\times$ 10² L E) 8.6 $\times$ 10² L

Question

Quizplus · Accepted Answer

To dissolve 5.0 g (5000 mg) of calcium carbonate, given that 5.8 mg dissolves in 1 L, you need 5000 mg / 5.8 mg/L = 862.07 L, which is approximately 8.6 × 10² L.

Calcium Carbonate,or Limestone,is Relatively Insoluble in Water ∘^{\circ}∘ C,only 58 Mg Will Dissolve in 1

Calcium Carbonate,or Limestone,is Relatively Insoluble in Water $^{\circ}$ C,only 58 Mg Will Dissolve in 1