How many bromide ions are in 0.55 g of iron(III)bromide?

Name: How many bromide ions are in 0.55 g of iron(III)bromide?
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Question

Quizplus · Accepted Answer

The molar mass of iron(III)bromide is 295.6 g/mol. So, 0.55 g of iron(III)bromide is 0.55 g / 295.6 g/mol = 0.00186 mol. Each mole of iron(III)bromide contains 3 moles of bromide ions. So, 0.00186 mol of iron(III)bromide contains 0.00186 mol * 3 = 0.00558 mol of bromide ions. 0.00558 mol of bromide ions is 0.00558 mol * 6.022 $\times$ 10²³ ions/mol = 3.4 $\times$ 10²¹ ions.

How Many Bromide Ions Are in 0 ×\times× 1021 Ions B) 3

How Many Bromide Ions Are in 0 $\times$ 10²¹ Ions
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