Pure copper may be produced by the reaction of copper(I) sulfide with oxygen gas as follows:
Cu₂S(s) + O₂(g) $\to$ 2Cu(s) + SO₂(g)
What mass of copper(I) sulfide is required in order to prepare 0.610 kg of copper metal?

Question

Pure copper may be produced by the reaction of copper(I) sulfide with oxygen gas as follows:
Cu₂S(s) + O₂(g)

\to

2Cu(s) + SO₂(g)
What mass of copper(I) sulfide is required in order to prepare 0.610 kg of copper metal?

Quizplus · Accepted Answer

The molar mass of Cu2S is 159.16 g/mol, and the molar mass of Cu is 63.55 g/mol. From the balanced equation, 1 mole of Cu2S produces 2 moles of Cu. To produce 0.610 kg (610 g) of Cu, we need (610 g / 63.55 g/mol) / 2 = 4.8 moles of Cu2S. Therefore, the mass of Cu2S required is 4.8 moles * 159.16 g/mol = 764 g or 0.764 kg.

Pure Copper May Be Produced by the Reaction of Copper(I)sulfide →\to→

Pure Copper May Be Produced by the Reaction of Copper(I)sulfide $\to$