How many moles of Mg3P2(s) can be produced from the reaction of 0.14 mol Mg(s) with 0.020 mol P4(s) ?
6 Mg(s) + P4(s) 2 Mg3P2(s)
A) 0.047 mol
B) 0.14 mol
C) 0.42 mol
D) 0.020 mol
E) 0.040 mol
Correct Answer:
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