Pure copper may be produced by the reaction of copper(I) sulfide with oxygen gas as follows:
Cu₂S(s) + O₂(g) $\to$ 2Cu(s) + SO₂(g)
If the reaction of 0.630 kg of copper(I) sulfide with excess oxygen produces 0.190 kg of copper metal,what is the percent yield?

Question

Pure copper may be produced by the reaction of copper(I) sulfide with oxygen gas as follows:
Cu₂S(s) + O₂(g)

\to

2Cu(s) + SO₂(g)
If the reaction of 0.630 kg of copper(I) sulfide with excess oxygen produces 0.190 kg of copper metal,what is the percent yield?

Quizplus · Accepted Answer

The Answer of Pure copper may be produced by the reaction of copper(I)sulfide with oxygen gas as follows: Cu₂S(s)+ O₂(g)$\to$ 2Cu(s)+ SO₂(g) If the reaction of 0.630 kg of copper(I)sulfide with excess oxygen produces 0.190 kg of copper metal,what is the percent yield?

Pure Copper May Be Produced by the Reaction of Copper(I)sulfide →\to→

Pure Copper May Be Produced by the Reaction of Copper(I)sulfide $\to$