Consider the fermentation reaction of glucose:
C₆H₁₂O₆ $\to$ 2C₂H₅OH + 2CO₂
A 1.00-mol sample of C₆H₁₂O₆was placed in a vat with 100 g of yeast.If 67.8 g of C₂H₅OH was obtained,what was the percent yield of C₂H₅OH?

Question

Consider the fermentation reaction of glucose:
C₆H₁₂O₆

\to

2C₂H₅OH + 2CO₂
A 1.00-mol sample of C₆H₁₂O₆was placed in a vat with 100 g of yeast.If 67.8 g of C₂H₅OH was obtained,what was the percent yield of C₂H₅OH?

Quizplus · Accepted Answer

Theoretical yield of C2H5OH is 92.0 g (from 1 mol glucose). Actual yield is 67.8 g. Percent yield = (67.8/92.0) * 100 = 73.6%.

Consider the Fermentation Reaction of Glucose: C6H12O6 →\to→ 2C2H5OH + 2CO2 a 1

Consider the Fermentation Reaction of Glucose:
C₆H₁₂O₆ $\to$ 2C₂H₅OH + 2CO₂
a 1