How many moles of sulfate ions are there in a 0.387-L solution of 0.927 M Al₂(SO₄)₃?

Name: How many moles of sulfate ions are there in a 0.387-L solution of 0.927 M Al 2 (SO 4 ) 3 ?
Brand: Quizplus
Rating: 4.8 (51 reviews)

Question

Quizplus · Accepted Answer

Al₂(SO₄)₃ dissociates into 2 Al³⁺ ions and 3 SO₄²⁻ ions. Therefore, 1 mole of Al₂(SO₄)₃ produces 3 moles of sulfate ions. The number of moles of Al₂(SO₄)₃ in the solution is 0.387 L × 0.927 M = 0.359 mol. Thus, the moles of sulfate ions are 0.359 mol × 3 = 1.08 mol.

How Many Moles of Sulfate Ions Are There in a 0.387-L