In order to dilute 35.5 mL of 0.533 M HCl to 0.100 M,the volume of water that must be added is

Question

Quizplus · Accepted Answer

Use the formula: M1V1 = M2V2

M1 = 0.533 M (initial concentration)
V1 = 35.5 mL (initial volume)
M2 = 0.100 M (final concentration)
V2 = ?

V2 = (M1V1) / M2
V2 = (0.533 M x 35.5 mL) / 0.100 M
V2 = 189.015 mL

The volume of water to add is the final volume (V2) minus the initial volume (V1):

V_water = V2 - V1
V_water = 189.015 mL - 35.5 mL
V_water = 153.515 mL

Therefore, the answer is E) 1.54 x 10^2 mL.

In Order to Dilute 35 ×\times× 102 ML ×\times× 10-3 ML ×\times× 102 ML