What volume of 2.52 M HCl is required to prepare 176.5 mL of 0.449 M HCl?

Question

Quizplus · Accepted Answer

We can use the formula:

(M1V1) = (M2V2)

Where:
M1 = 2.52 M (from the concentrated HCl)
V1 = volume of concentrated HCl we are looking for (in mL)
M2 = 0.449 M (from the diluted HCl)
V2 = 176.5 mL (given in the problem)

Rearranging the formula, we get:

V1 = (M2V2) / M1
V1 = (0.449 M)(176.5 mL) / 2.52 M
V1 = 31.4 mL

Therefore, we need 31.4 mL of 2.52 M HCl to prepare 176.5 mL of 0.449 M HCl.

What Volume of 2 ×\times× 102 ML B) 1 ×\times× 102 ML C) 31

What Volume of 2 $\times$ 10² ML
B) 1 $\times$ 10² ML
C) 31