A mass of 0.4113 g of an unknown acid,HA,is titrated with NaOH.If the acid reacts with 28.10 mL of 0.1055 M NaOH(aq),what is the molar mass of the acid?

Question

Quizplus · Accepted Answer

To find the molar mass of the acid, first calculate the moles of NaOH used: $0.02810 \, \text{L} \times 0.1055 \, \text{mol/L} = 0.00296555 \, \text{mol NaOH}$. Assuming a 1:1 reaction, moles of HA = moles of NaOH = 0.00296555 mol. Molar mass = mass/moles = $0.4113 \, \text{g} / 0.00296555 \, \text{mol} = 138.7 \, \text{g/mol}$.

A Mass of 0 ×\times× 10-3 G/mol B) 9

A Mass of 0 $\times$ 10^-3 G/mol
B) 9