An unknown diprotic acid (H₂A)requires 44.39 mL of 0.111 M NaOH to completely neutralize a 0.580 g sample.Calculate the approximate molar mass of the acid.

Question

Quizplus · Accepted Answer

A diprotic acid reacts with NaOH in a 1:2 ratio. Moles of NaOH = 0.04439 L * 0.111 mol/L = 0.004927 mol. Moles of H2A = 0.004927 mol / 2 = 0.0024635 mol. Molar mass = 0.580 g / 0.0024635 mol = 235 g/mol.

An Unknown Diprotic Acid (H2A)requires 44

An Unknown Diprotic Acid (H₂A)requires 44