The reaction of HCl with NaOH is represented by the equation
HCl(aq) + NaOH(aq) $\to$ NaCl(aq) + H₂O(l)
What volume of 0.686 M HCl is required to titrate 42.8 mL of 0.334 M NaOH?

Question

The reaction of HCl with NaOH is represented by the equation HCl(aq)+ NaOH(aq)$\to$ NaCl(aq)+ H₂O(l) What volume of 0.686 M HCl is required to titrate 42.8 mL of 0.334 M NaOH?

Quizplus · Accepted Answer

In order to solve this problem, we need to use the equation:
M1V1 = M2V2

where M1 is the molarity of the acid, V1 is the volume of acid used, M2 is the molarity of the base, and V2 is the volume of the base used.

Plugging in the values we know, we get:

(0.686 M)(V1) = (0.334 M)(0.0428 L)
V1 = 0.0262 L = 26.2 mL

Therefore, the volume of HCl needed to titrate the NaOH is 26.2 mL, which is closest to answer choice C (20.8 mL).

The Reaction of HCl with NaOH Is Represented by the Equation