A 50.00-mL sample of a weak monoprotic acid is titrated with 0.0955 M NaOH.At the endpoint,it is found that 32.56 mL of titrant was used.What was the concentration of the weak acid?

Question

Quizplus · Accepted Answer

Firstly, we can calculate the number of moles of NaOH used:
0.0955 M x 0.03256 L = 0.00311 moles of NaOH

Since the acid is monoprotic (meaning it only donates one hydrogen ion), the number of moles of acid and moles of NaOH are equal at the equivalence point.

Therefore, we can use the volume and concentration of NaOH used to calculate the concentration of the acid:
0.00311 moles of NaOH / 0.05000 L = 0.0622 M

The correct answer is A, with a concentration of 0.0622 M.

A 5000-ML Sample of a Weak Monoprotic Acid Is Titrated with with 0.0955