A sample of helium gas occupies 14.7 L at 23°C and 0.956 atm.What volume will it occupy at 40°C and 1.20 atm?
A) 19.5 L
B) 20.4 L
C) 11.1 L
D) 12.4 L
E) 14.9 L

Question

Quizplus · Accepted Answer

We can use the combined gas law to solve for the final volume:

(P₁V₁/T₁) = (P₂V₂/T₂)

Where:
P₁ = 0.956 atm (initial pressure)
V₁ = 14.7 L (initial volume)
T₁ = 296 K (23°C converted to Kelvin)
P₂ = 1.20 atm (final pressure)
V₂ = ? (final volume we're solving for)
T₂ = 313 K (40°C converted to Kelvin)

Plugging in the values and solving for V₂:

(0.956×14.7)/296 = (1.20×V₂)/313

V₂ = (0.956×14.7×313)/(296×1.20) = 12.4 L

Therefore, the answer is D) 12.4 L.

A Sample of Helium Gas Occupies 14