A 45.0 L gas cylinder contains 988 g He at 23 $\circ$ C.What is the pressure inside the cylinder? (R = 0.08206 L.atm/mol.K)

Question

Quizplus · Accepted Answer

First, convert the temperature to Kelvin:

23°F + 459.67 = 482.67 K

Then, convert the mass of He to moles:

988 g He x (1 mol He/4.003 g He) = 246.7 mol He

Next, use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

Solving for P:

P = nRT/V

P = (246.7 mol)(0.08206 L•atm/mol•K)(482.67 K)/(45.0 L)

P = 133 atm

Therefore, the answer is D) 133 atm.

A 450 L Gas Cylinder Contains 988 G He at 23