The Lattice Energy of NaBr Is -752 KJ/mol $\to$ NaBr(s)
B) Na(g)+ Br(g)

The lattice energy of NaBr is -752 kJ/mol.This energy corresponds to which reaction below?

A) Na(s) + 1/2 Br₂(g) $\to$ NaBr(s)
B) Na(g) + Br(g) $\to$ NaBr(s)
C) Na(g) + Br(g) $\to$ NaBr(s)
D) Na⁺(g) + Br^-(g) $\to$ NaBr(s)
E) Na⁺(aq) + Br^-(aq) $\to$ NaBr(s)