The reaction,A + 2B $\to$ B₂ + A,proceeds by the following mechanism: (A is a catalyst.)
A + B $\to$ AB $~~~~~~~~$ $~~~~~~~~$ (slow)
AB + B $\to$ B₂ + A $~~~~~~~~~~$ (fast)
What is the rate law expression for this reaction?

Question

The reaction,A + 2B

\to

B₂ + A,proceeds by the following mechanism: (A is a catalyst.)
A + B

\to

AB

~~~~~~~~

~~~~~~~~

(slow)
AB + B

\to

B₂ + A

~~~~~~~~~~

(fast)
What is the rate law expression for this reaction?

Quizplus · Accepted Answer

The rate-determining step in this mechanism is the slow step, which involves only A and B. Therefore, the rate law expression must include both A and B, and their exponents must match their stoichiometric coefficients in the slow step. Thus, the rate law expression is Rate = k[A][B].

The Reaction,A + 2B →\to→ B2 + A,proceeds by the Following Mechanism: (A Is a Following

The Reaction,A + 2B $\to$ B₂ + A,proceeds by the Following Mechanism: (A Is a Following