What is the pH of a solution prepared by dissolving 0.581 L of HCl(g),measured at STP,in enough water such that the total volume of the solution is 2.00 L? (R = 0.0821 L · atm/K·mol)

Question

Quizplus · Accepted Answer

At STP, 1 mole of gas occupies 22.4 L. Therefore, 0.581 L of HCl gas is 0.581/22.4 = 0.0259 moles. Since HCl is a strong acid, it dissociates completely in water, so the concentration of H+ ions is 0.0259 moles/2.00 L = 0.01295 M. The pH is -log(0.01295) = 1.887.

What Is the PH of a Solution Prepared by Dissolving