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H3PO3 Is a Diprotic Weak Acid

Question 41

Multiple Choice

H3PO3 is a diprotic weak acid.What is the balanced equilibrium defined as Kb2 of H3PO3?


A) H3PO3(aq) + H2O(l) H<sub>3</sub>PO<sub>3</sub> is a diprotic weak acid.What is the balanced equilibrium defined as K<sub>b2</sub> of H<sub>3</sub>PO<sub>3</sub>? A) H<sub>3</sub>PO<sub>3</sub>(aq) + H<sub>2</sub>O(l) H<sub>3</sub>O<sup>+</sup>(aq) + H<sub>2</sub>PO<sub>3</sub><sup>-</sup>(aq) B) H<sub>2</sub>PO<sub>3</sub><sup>-</sup>(aq) + H<sub>2</sub>O(l) H<sub>3</sub>O<sup>+</sup>(aq) + HPO<sub>3</sub><sup>2-</sup>(aq) C) HPO<sub>3</sub><sup>2-</sup>(aq) <sup> </sup>+ H<sub>2</sub>O(l) OH<sup>-</sup>(l) + H<sub>2</sub>PO<sub>3</sub><sup>-</sup>(aq) D) H<sub>2</sub>PO<sub>3</sub><sup>-</sup>(aq) + H<sub>2</sub>O(l) OH<sup>-</sup>(l) + H<sub>3</sub>PO<sub>3</sub>(aq) E) HPO<sub>3</sub><sup>2-</sup>(aq) + H<sub>2</sub>O(l) OH<sup>-</sup>(aq) + H<sub>3</sub>PO<sub>3</sub>(aq) H3O+(aq) + H2PO3-(aq)
B) H2PO3-(aq) + H2O(l) H<sub>3</sub>PO<sub>3</sub> is a diprotic weak acid.What is the balanced equilibrium defined as K<sub>b2</sub> of H<sub>3</sub>PO<sub>3</sub>? A) H<sub>3</sub>PO<sub>3</sub>(aq) + H<sub>2</sub>O(l) H<sub>3</sub>O<sup>+</sup>(aq) + H<sub>2</sub>PO<sub>3</sub><sup>-</sup>(aq) B) H<sub>2</sub>PO<sub>3</sub><sup>-</sup>(aq) + H<sub>2</sub>O(l) H<sub>3</sub>O<sup>+</sup>(aq) + HPO<sub>3</sub><sup>2-</sup>(aq) C) HPO<sub>3</sub><sup>2-</sup>(aq) <sup> </sup>+ H<sub>2</sub>O(l) OH<sup>-</sup>(l) + H<sub>2</sub>PO<sub>3</sub><sup>-</sup>(aq) D) H<sub>2</sub>PO<sub>3</sub><sup>-</sup>(aq) + H<sub>2</sub>O(l) OH<sup>-</sup>(l) + H<sub>3</sub>PO<sub>3</sub>(aq) E) HPO<sub>3</sub><sup>2-</sup>(aq) + H<sub>2</sub>O(l) OH<sup>-</sup>(aq) + H<sub>3</sub>PO<sub>3</sub>(aq) H3O+(aq) + HPO32-(aq)
C) HPO32-(aq) + H2O(l) H<sub>3</sub>PO<sub>3</sub> is a diprotic weak acid.What is the balanced equilibrium defined as K<sub>b2</sub> of H<sub>3</sub>PO<sub>3</sub>? A) H<sub>3</sub>PO<sub>3</sub>(aq) + H<sub>2</sub>O(l) H<sub>3</sub>O<sup>+</sup>(aq) + H<sub>2</sub>PO<sub>3</sub><sup>-</sup>(aq) B) H<sub>2</sub>PO<sub>3</sub><sup>-</sup>(aq) + H<sub>2</sub>O(l) H<sub>3</sub>O<sup>+</sup>(aq) + HPO<sub>3</sub><sup>2-</sup>(aq) C) HPO<sub>3</sub><sup>2-</sup>(aq) <sup> </sup>+ H<sub>2</sub>O(l) OH<sup>-</sup>(l) + H<sub>2</sub>PO<sub>3</sub><sup>-</sup>(aq) D) H<sub>2</sub>PO<sub>3</sub><sup>-</sup>(aq) + H<sub>2</sub>O(l) OH<sup>-</sup>(l) + H<sub>3</sub>PO<sub>3</sub>(aq) E) HPO<sub>3</sub><sup>2-</sup>(aq) + H<sub>2</sub>O(l) OH<sup>-</sup>(aq) + H<sub>3</sub>PO<sub>3</sub>(aq) OH-(l) + H2PO3-(aq)
D) H2PO3-(aq) + H2O(l) H<sub>3</sub>PO<sub>3</sub> is a diprotic weak acid.What is the balanced equilibrium defined as K<sub>b2</sub> of H<sub>3</sub>PO<sub>3</sub>? A) H<sub>3</sub>PO<sub>3</sub>(aq) + H<sub>2</sub>O(l) H<sub>3</sub>O<sup>+</sup>(aq) + H<sub>2</sub>PO<sub>3</sub><sup>-</sup>(aq) B) H<sub>2</sub>PO<sub>3</sub><sup>-</sup>(aq) + H<sub>2</sub>O(l) H<sub>3</sub>O<sup>+</sup>(aq) + HPO<sub>3</sub><sup>2-</sup>(aq) C) HPO<sub>3</sub><sup>2-</sup>(aq) <sup> </sup>+ H<sub>2</sub>O(l) OH<sup>-</sup>(l) + H<sub>2</sub>PO<sub>3</sub><sup>-</sup>(aq) D) H<sub>2</sub>PO<sub>3</sub><sup>-</sup>(aq) + H<sub>2</sub>O(l) OH<sup>-</sup>(l) + H<sub>3</sub>PO<sub>3</sub>(aq) E) HPO<sub>3</sub><sup>2-</sup>(aq) + H<sub>2</sub>O(l) OH<sup>-</sup>(aq) + H<sub>3</sub>PO<sub>3</sub>(aq) OH-(l) + H3PO3(aq)
E) HPO32-(aq) + H2O(l) H<sub>3</sub>PO<sub>3</sub> is a diprotic weak acid.What is the balanced equilibrium defined as K<sub>b2</sub> of H<sub>3</sub>PO<sub>3</sub>? A) H<sub>3</sub>PO<sub>3</sub>(aq) + H<sub>2</sub>O(l) H<sub>3</sub>O<sup>+</sup>(aq) + H<sub>2</sub>PO<sub>3</sub><sup>-</sup>(aq) B) H<sub>2</sub>PO<sub>3</sub><sup>-</sup>(aq) + H<sub>2</sub>O(l) H<sub>3</sub>O<sup>+</sup>(aq) + HPO<sub>3</sub><sup>2-</sup>(aq) C) HPO<sub>3</sub><sup>2-</sup>(aq) <sup> </sup>+ H<sub>2</sub>O(l) OH<sup>-</sup>(l) + H<sub>2</sub>PO<sub>3</sub><sup>-</sup>(aq) D) H<sub>2</sub>PO<sub>3</sub><sup>-</sup>(aq) + H<sub>2</sub>O(l) OH<sup>-</sup>(l) + H<sub>3</sub>PO<sub>3</sub>(aq) E) HPO<sub>3</sub><sup>2-</sup>(aq) + H<sub>2</sub>O(l) OH<sup>-</sup>(aq) + H<sub>3</sub>PO<sub>3</sub>(aq) OH-(aq) + H3PO3(aq)

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