Suppose 50.00 mL of 2.0 $\times$ 10^-6 M Fe(NO₃)₃ is added to 50.00 mL of 2.0 $\times$ 10^-4 M KIO₃.Which of the following statements is true? For Fe(IO₃)₃,K_sp = 1.0 $\times$ 10^-14. A) A precipitate forms because Q_c K_sp. B) A precipitate forms because Q_c

Question

Suppose 50.00 mL of 2.0 $\times$ 10^-6 M Fe(NO₃)₃ is added to 50.00 mL of 2.0 $\times$ 10^-4 M KIO₃.Which of the following statements is true? For Fe(IO₃)₃,K_sp = 1.0 $\times$ 10^-14. A) A precipitate forms because Q_c > K_sp. B) A precipitate forms because Q_c < K_sp. C) No precipitate forms because Q_c < K_sp. D) No precipitate forms because Q_c = K_sp. E) No precipitate forms because Q_c > K_sp.

Quizplus · Accepted Answer

The reaction quotient Qc is calculated using the concentrations of Fe3+ and IO3- ions in the mixed solution. After mixing, the concentrations are 1.0 x 10^-6 M for Fe3+ and 1.0 x 10^-4 M for IO3-. Qc = [Fe3+][IO3-]^3 = (1.0 x 10^-6)(1.0 x 10^-4)^3 = 1.0 x 10^-18, which is less than Ksp (1.0 x 10^-14), so no precipitate forms.

Suppose 50 ×\times× 10-6 M Fe(NO3)3 Is Added to 50 ×\times× 10-4 M KIO3

Suppose 50 $\times$ 10^-6 M Fe(NO₃)₃ Is Added to 50 $\times$ 10^-4 M KIO₃