Given the following,determine $\Delta$_rG° at 298 K for the precipitation reaction, Ag⁺(aq)+I^-(aq)$\to$ AgI(s) A) -91.7 kJ/mol-rxn B) -40.7 kJ/mol-rxn C) 91.7 kJ/mol-rxn D) 40.7 kJ/mol-rxn E) 62.5 kJ/mol-rxn

Question

Quizplus · Accepted Answer

The standard Gibbs free energy change for the reaction can be calculated using the formula: ΔG° = ΣΔG°f(products) - ΣΔG°f(reactants). For the reaction Ag⁺(aq) + I⁻(aq) → AgI(s), ΔG° = ΔG°f(AgI) - [ΔG°f(Ag⁺) + ΔG°f(I⁻)]. Substituting the given values: ΔG° = (-66.2) - [77.12 + (-51.59)] = -91.7 kJ/mol-rxn.

Given the Following,determine Δ\DeltaΔ rG° at 298 K for the Precipitation Reaction, Ag+(aq)+I-(aq)

Given the Following,determine $\Delta$ _rG° at 298 K for the Precipitation Reaction,
Ag⁺(aq)+I^-(aq)