What is the correct cell notation for a voltaic cell based on the reaction below? Cu²⁺(aq)+ Fe(s)$\to$ Cu(s)+ Fe²⁺(aq) A) Cu(s)| Cu²⁺(aq)|| Fe²⁺(aq)| Fe(s) B) Fe(s)|| Fe²⁺(aq),Cu²⁺(aq)| Cu(s) C) Cu(s)|| Cu²⁺(aq),Fe²⁺(aq)|| Fe(s) D) Cu(s)| Fe²⁺(aq)|| Cu²⁺(aq)| Fe(s) E) Fe(s)| Fe²⁺(aq)|| Cu²⁺(aq)| Cu(s)

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Quizplus · Accepted Answer

In a voltaic cell, the anode (oxidation) is on the left and the cathode (reduction) is on the right. Fe is oxidized to Fe²⁺, and Cu²⁺ is reduced to Cu, so the correct notation is Fe(s)| Fe²⁺(aq)|| Cu²⁺(aq)| Cu(s).

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