In the following electrochemical cell,what is the reduction half reaction? Cu(s)| Cu²⁺(aq)|| Fe³⁺(aq),Fe²⁺(aq)| Pt(s) A) Fe³^-(aq)+ e^-$\to$Fe²(aq) B) Fe^2-(aq)+ e^-$\to$ Fe³⁺(aq) C) Fe²⁺(aq)+ Pt(s)$\to$Fe³⁺0(aq)+ e^- D) Cu²⁺(aq)$\to$Cu(s)+ 2e^- E) Cu(s)$\to$Cu²⁺(aq)+ 2e^-

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Quizplus · Accepted Answer

The reduction half reaction involves the gain of electrons, which causes a reduction in the oxidation state of a species. In the given cell, Fe in FeSO4(aq) is being reduced to Fe in FeS2O12(aq) by gaining an electron, so the reduction half reaction is FeSO4(aq) + e- -> FeS2O12(aq). This option A correctly represents this reduction half reaction. The other choices either have the wrong species being reduced or the wrong direction of electron flow.

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