Calculate
for the electrochemical cell below,
Ag(s) | AgCl(s) | Cl-(aq,1.0 M) || Cu2+(aq,1.0 M) | Cu(s)
Given the following standard reduction potentials.
Cu2+(aq) + 2 e- Cu(s) E = +0.337 V
AgCl(s) + e- Ag(s) + Cl-(aq) E = +0.222 V
A) -0.115 V
B) -0.107 V
C) +0.115 V
D) +0.452 V
E) +0.559 V
Correct Answer:
Verified
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