When an aqueous solution of sodium sulfate is electrolyzed,what are the expected products? Reduction Half-Reaction$~~~~~~~~$$~~~~~~~~$E° (V) $\to$ Na(s) $~~~~~~~~$$~~~~~~~~$$~~~~~~~~$-2.71 2H₂O(l)+ 2e^- $\to$ H₂(g)+ 2OH^-(aq) $~~~~ ~~$$~ ~$-0.83 2H⁺(aq)+ 2e^- $\to$ H₂(g) $~~~~~~~~$$~~~~~~~~$$~~~~~~~~$0.00 O₂(g)+ 4H⁺(aq)+ 4e^- $\to$ 2H₂O(l) $~~~~~~~~$$~~ ~ $1.23 S₂O₈^2-(aq)+ 2e^- $\to$ 2SO₄^2-(aq) $~~~~~~~~$$~~~~~~ ~$2.01 A) Na(s)and H₂(g) B) H₂(g),OH^-(aq),O₂(g),and H⁺(aq) C) O₂(g),H⁺(aq),and Na(s) D) H₂(g),OH^-(aq),and Na(s) E) H₂(g),OH^-(aq),and S₂O₈^2-(aq)

Question

Quizplus · Accepted Answer

When sodium sulfate is electrolyzed, the reduction half-reaction takes place at the cathode and the oxidation half-reaction takes place at the anode.

Reduction Half-Reaction:
2H2O(l) + 2e- -> H2(g) + 2OH-(aq)          E° = -0.83 V

Oxidation Half-Reaction:
2H2O(l) -> O2(g) + 4H+(aq) + 4e-                E° = -1.23 V

At the cathode, water is reduced to hydrogen gas and hydroxide ions, while at the anode, water is oxidized to oxygen gas, hydrogen ions, and electrons. The hydrogen ions produced at the anode react with the sulfate ions in solution to form sulfuric acid.

Therefore, the expected products are hydrogen gas, oxygen gas, sulfuric acid, and hydroxide ions. Choice B includes all of these expected products.

When an Aqueous Solution of Sodium Sulfate Is Electrolyzed,what Are ~~~~~~~~

When an Aqueous Solution of Sodium Sulfate Is Electrolyzed,what Are $~~~~~~~~$