What mass of sulfur dioxide gas would be produced from 6.00 kg of coal which contains 1.15 % sulfur by mass?

Question

Quizplus · Accepted Answer

- First, we need to find the mass of sulfur in 6.00 kg of coal:

mass of sulfur = mass of coal x % sulfur by mass
mass of sulfur = 6.00 kg x 0.0115
mass of sulfur = 0.069 kg

- Next, we use the stoichiometry of the reaction between sulfur and oxygen to find the mass of sulfur dioxide produced:

S(s) + O2(g) → SO2(g)

1 mole of sulfur produces 1 mole of sulfur dioxide.
The molar mass of sulfur is 32.06 g/mol.
So, 0.069 kg of sulfur is equal to 2.15 moles of sulfur.

2.15 moles of sulfur dioxide = 2.15 x 64 g/mol (molar mass of SO2)
2.15 moles of sulfur dioxide = 138.4 g

Therefore, the mass of sulfur dioxide produced from 6.00 kg of coal is 138 g (choice D).

What Mass of Sulfur Dioxide Gas Would Be Produced from 6.00