The rate constant for the decay of a radioactive isotope is 4.231 $\times$ 10^-3/ day.What is the half-life of this isotope?

Question

Quizplus · Accepted Answer

The half-life (t₁/₂) of a radioactive isotope can be calculated using the formula t₁/₂ = 0.693 / k, where k is the rate constant. Substituting the given rate constant (4.231 x 10^-3 / day) into the formula gives t₁/₂ = 0.693 / 4.231 x 10^-3 = 163.8 days.

The Rate Constant for the Decay of a Radioactive Isotope ×\times×

The Rate Constant for the Decay of a Radioactive Isotope $\times$