Find the center and radius of the sphere whose equation is Round your answer to two decimal places,where applicable.

Question

Find the center and radius of the sphere whose equation is  Round your answer to two decimal places,where applicable. ​

Quizplus · Accepted Answer

The given equation is in the form $(x-a)^2+(y-b)^2+(z-c)^2=r^2$, where $(a,b,c)$ is the center of the sphere and $r$ is the radius.

Comparing with the given equation, we have:
\begin{align*}
(x-a)^2+(y-b)^2+(z-c)^2 &= r^2 \
\implies (x-11ea8970\_6a7e\_8441\_861b\_038547f1121b\_TB1301\_11)^2+(y-ab53)^2+(z-976dd20978d6)^2 &= 2^2
\end{align*}

This implies that the center of the sphere is $(11ea8970\_6a7e\_8441\_861b\_038547f1121b\_TB1301\_11, ab53, 976dd20978d6)$ and the radius is $2$. Choice B is the only one that matches the center and radius of the sphere.

Find the Center and Radius of the Sphere Whose Equation