Factor the sum or difference of cubes. 27n³ + 8 A) (3n - 2)³ B) (3n + 2)³ C) (3n + 2)(9n² - 6n + 4) D) (3n + 2)(9n² + 6n + 4) E) (3n - 2)(9n² - 6n + 4)

Question

Quizplus · Accepted Answer

The sum of cubes can be factored as $a^3 + b^3 = (a + b)(a^2 - ab + b^2)$. Here, $27n^3 + 8$ can be rewritten as $(3n)^3 + 2^3$, which factors into $(3n + 2)((3n)^2 - 3n*2 + 2^2)$ or $(3n + 2)(9n^2 - 6n + 4)$.

Factor the Sum or Difference of Cubes