How much water must be added to 8 liters of a 51% saline solution to dilute it to a 36% saline solution? Round answer to nearest tenth of a liter.

Question

Quizplus · Accepted Answer

The amount of salt in the original solution is 51% of 8 liters, which is 0.51 * 8 = 4.08 liters. To find the total volume of the new solution that results in a 36% saline solution, we use the equation 4.08 = 0.36 * (8 + x), where x is the amount of water added. Solving for x gives x = (4.08 / 0.36) - 8 ≈ 3.3 liters.

How Much Water Must Be Added to 8 Liters of a 51