A solution of a pure chiral molecule has a specific rotation of -23.1°.What is the specific rotation of a solution that is 83% (+)enantiomer and 17% (-)enantiomer?

Question

Quizplus · Accepted Answer

The specific rotation of a mixture of enantiomers is the weighted average of the specific rotations of the pure enantiomers. In this case, the specific rotation of the (+) enantiomer is +23.1° and the specific rotation of the (-) enantiomer is -23.1°. The specific rotation of the mixture is therefore:(0.83 x 23.1°) + (0.17 x -23.1°) = 15.0°

A Solution of a Pure Chiral Molecule Has a Specific °\degree°

A Solution of a Pure Chiral Molecule Has a Specific $\degree$