The conversion of glucose-6-phosphate to fructose-6-phosphate has a $\Delta$G°´ of +1.7 kJ/mol but within a typical cell, the $\Delta$G is -2.9 kJ/mol. What can be said about the value of K_eq and Q?

Question

Quizplus · Accepted Answer

Under standard conditions, a positive ΔG°´ indicates that the reaction is not spontaneous, implying K_eq < 1. In the cell, a negative ΔG indicates the reaction is spontaneous, suggesting that Q < K_eq, which means Q < 1 given the context of K_eq being < 1.

The Conversion of Glucose-6-Phosphate to Fructose-6-Phosphate Has A Δ\DeltaΔ G°´ of +17 KJ/mol but Within a Typical Cell, The \Delta

The Conversion of Glucose-6-Phosphate to Fructose-6-Phosphate Has A $\Delta$ G°´ of +17 KJ/mol but Within a Typical Cell, The \Delta