With respect to carbons 1 and 2 of the intermediate in the conversion of glucose-6-phosphate to fructose-6-phosphate, which of the following would best describe this intermediate?

Question

Quizplus · Accepted Answer

The intermediate in the conversion of glucose-6-phosphate to fructose-6-phosphate is an enediol, which is a molecule containing two hydroxyl groups (-OH) on adjacent carbons with a double bond between them (C=C-OH). This intermediate is formed when a phosphate group is removed from carbon 1 and a hydrogen atom is removed from carbon 2 of glucose-6-phosphate, resulting in a double bond between the two carbons and the formation of two hydroxyl groups on adjacent carbons. This enediol then quickly tautomerizes (shifts its double bond and proton) to form fructose-6-phosphate, which is a ketone with a single hydroxyl group on carbon 6.

With Respect to Carbons 1 and 2 of the Intermediate