What is the value of ΔH in kcal/mole for the reaction shown? (CH3) 3C-H + Cl-Cl → (CH3) 3C-Cl + H-Cl
Bond energies are: (CH3) 3C-H = 91 kcal/mole
(CH3) 3C-Cl = 78.5 kcal/mole
Cl-Cl = 58 kcal/mole
H-Cl = 103 kcal/mole
A) +32.5
B) -57.5
C) -32.5
D) +57.5
E) -8.5
Correct Answer:
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