Given the bond dissociation energies below (in kcal/mol) ,estimate the ΔH° for the propagation step (CH3) 2CH∙ + Cl2 → (CH3) 2CHCl + Cl∙.
CH3CH2CH2-H 98
(CH3) 2CH-H 95
Cl-Cl 58
H-Cl 103
CH3CH2CH2-Cl 81
(CH3) 2CH-Cl 80
A) -22 kcal/mol
B) +22 kcal/mol
C) -40 kcal/mol
D) +45 kcal/mol
E) -45 kcal/mol
Correct Answer:
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