When (R)-2-bromobutane reacts with Cl₂/hv,which of the following is true?

Question

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When (R)-2-bromobutane reacts with Cl₂/hv, two possible products can be formed: I. (R)-2-chlorobutane II. (S)-2-chlorobutane As the reaction is a free radical halogenation, both of these products can be formed. However, they will not be formed in equal amounts as the reactant is a chiral molecule and the reaction will proceed with retention of configuration. Therefore, the chlorine atom will be introduced on the same side as the bromine, leading to a mixture of the (R) and (S) forms of the product. As a result, I and II will be formed in unequal amounts.

When (R)-2-Bromobutane Reacts with Cl2/hv,which of the Following Is True

When (R)-2-Bromobutane Reacts with Cl₂/hv,which of the Following Is True