How many sodium ions are present in 325 mL of 0.850 M Na₂SO₄?

Question

Quizplus · Accepted Answer

To determine the number of sodium ions present, we first need to find the molar concentration of Na in the solution. The compound Na₂SO₄ can be broken down into Na+ and SO42- ions. Therefore, the molar concentration of Na will be the same as the molar concentration of Na₂SO₄. Molarity = moles of solute / liters of solution Since we are given the volume of the solution in milliliters, we must convert it to liters: 325 mL = 0.325 L Molarity of Na₂SO₄ = 0.850 M Now we can use the formula: moles of solute = Molarity x liters of solution moles of Na = 0.850 M x 0.325 L = 0.27625 moles Finally, we can use Avogadro's number to convert moles to number of ions: 1 mole of any substance = 6.022 x 10^23 particles (Avogadro's number) 0.27625 moles of Na ions = 0.27625 x 6.022 x 10^23 = 1.6618725 x 10^23 Rounded to three significant figures, the number of Na ions present is 3.33 x 10^23. Therefore, the correct answer is B.

How Many Sodium Ions Are Present in 325 ML of 0.850