A 275-g sample of nickel at l00.0°C is placed in 100.0 mL of water at 22.0°C.What is the final temperature of the water? Assume that no heat is lost to or gained from the surroundings.Specific heat capacity of nickel = 0.444 J/(g·K)

Question

Quizplus · Accepted Answer

The heat lost by nickel equals the heat gained by water. Using the formula q = mcΔT, we set up the equation: (275 g)(0.444 J/g·K)(T_final - 100°C) = (100 g)(4.18 J/g·K)(T_final - 22°C). Solving for T_final gives approximately 39.6°C.

A 275-G Sample of Nickel at L00