Calcium hydroxide,which reacts with carbon dioxide to form calcium carbonate,was used by the ancient Romans as mortar in stone structures.The reaction for this process is

What is the enthalpy change if 3.8 mol of calcium carbonate is formed?

Question

Calcium hydroxide,which reacts with carbon dioxide to form calcium carbonate,was used by the ancient Romans as mortar in stone structures.The reaction for this process is

What is the enthalpy change if 3.8 mol of calcium carbonate is formed?

Quizplus · Accepted Answer

From the balanced equation, we see that the reaction produces 1 mol of CaCO3 for every 1 mol of Ca(OH)2 consumed. Therefore, the enthalpy change for the production of 3.8 mol of CaCO3 is simply 3.8 times the enthalpy change given in the equation. Using the given value of -65.2 kJ/mol for the enthalpy change, we get:

Enthalpy change = -65.2 kJ/mol x 3.8 mol = -247.76 kJ

We round to -260 kJ, which is choice D.

Calcium Hydroxide,which Reacts with Carbon Dioxide to Form Calcium Carbonate,was