Examine the following half-reactions and select the strongest oxidizing agent among the substances.
[PtCl4]2-(aq) + 2e- ![Examine the following half-reactions and select the strongest oxidizing agent among the substances. [PtCl<sub>4</sub>]<sup>2-</sup>(aq) + 2e<sup>-</sup> Pt(s) + 4Cl<sup>-</sup>(aq) ;E° = 0.755 V RuO<sub>4</sub>(s) + 8H<sup>+</sup>(aq) + 8e<sup>-</sup> Ru(s) + 4H<sub>2</sub>O(l) ;E° = 1.038 V FeO<sub>4</sub><sup>2-</sup>(aq) + 8H<sup>+</sup>(aq) + 3e<sup>-</sup> Fe<sup>3+</sup>(aq) + 4H<sub>2</sub>O(l) ;E° = 2.07 V H<sub>4</sub>XeO<sub>6</sub>(aq) + 2H<sup>+</sup>(aq) + 2e<sup>-</sup> XeO<sub>3</sub>(aq) + 3H<sub>2</sub>O(l) ;E° = 2.42 V A) [PtCl<sub>4</sub>]<sup>2-</sup>(aq) B) RuO<sub>4</sub>(s) C) HFeO<sub>4</sub><sup>-</sup> (aq) D) H<sub>4</sub>XeO<sub>6</sub>(aq) E) Cl<sup>-</sup>(aq)](https://d2lvgg3v3hfg70.cloudfront.net/TB5832/11ea8a63_0609_ead4_9a87_575d1b046e74_TB5832_11.jpg)
Pt(s) + 4Cl-(aq) ;E° = 0.755 V
RuO4(s) + 8H+(aq) + 8e- ![Examine the following half-reactions and select the strongest oxidizing agent among the substances. [PtCl<sub>4</sub>]<sup>2-</sup>(aq) + 2e<sup>-</sup> Pt(s) + 4Cl<sup>-</sup>(aq) ;E° = 0.755 V RuO<sub>4</sub>(s) + 8H<sup>+</sup>(aq) + 8e<sup>-</sup> Ru(s) + 4H<sub>2</sub>O(l) ;E° = 1.038 V FeO<sub>4</sub><sup>2-</sup>(aq) + 8H<sup>+</sup>(aq) + 3e<sup>-</sup> Fe<sup>3+</sup>(aq) + 4H<sub>2</sub>O(l) ;E° = 2.07 V H<sub>4</sub>XeO<sub>6</sub>(aq) + 2H<sup>+</sup>(aq) + 2e<sup>-</sup> XeO<sub>3</sub>(aq) + 3H<sub>2</sub>O(l) ;E° = 2.42 V A) [PtCl<sub>4</sub>]<sup>2-</sup>(aq) B) RuO<sub>4</sub>(s) C) HFeO<sub>4</sub><sup>-</sup> (aq) D) H<sub>4</sub>XeO<sub>6</sub>(aq) E) Cl<sup>-</sup>(aq)](https://d2lvgg3v3hfg70.cloudfront.net/TB5832/11ea8a63_0609_ead5_9a87_8914d7a37146_TB5832_11.jpg)
Ru(s) + 4H2O(l) ;E° = 1.038 V
FeO42-(aq) + 8H+(aq) + 3e- ![Examine the following half-reactions and select the strongest oxidizing agent among the substances. [PtCl<sub>4</sub>]<sup>2-</sup>(aq) + 2e<sup>-</sup> Pt(s) + 4Cl<sup>-</sup>(aq) ;E° = 0.755 V RuO<sub>4</sub>(s) + 8H<sup>+</sup>(aq) + 8e<sup>-</sup> Ru(s) + 4H<sub>2</sub>O(l) ;E° = 1.038 V FeO<sub>4</sub><sup>2-</sup>(aq) + 8H<sup>+</sup>(aq) + 3e<sup>-</sup> Fe<sup>3+</sup>(aq) + 4H<sub>2</sub>O(l) ;E° = 2.07 V H<sub>4</sub>XeO<sub>6</sub>(aq) + 2H<sup>+</sup>(aq) + 2e<sup>-</sup> XeO<sub>3</sub>(aq) + 3H<sub>2</sub>O(l) ;E° = 2.42 V A) [PtCl<sub>4</sub>]<sup>2-</sup>(aq) B) RuO<sub>4</sub>(s) C) HFeO<sub>4</sub><sup>-</sup> (aq) D) H<sub>4</sub>XeO<sub>6</sub>(aq) E) Cl<sup>-</sup>(aq)](https://d2lvgg3v3hfg70.cloudfront.net/TB5832/11ea8a63_0609_ead6_9a87_af32046081f6_TB5832_11.jpg)
Fe3+(aq) + 4H2O(l) ;E° = 2.07 V
H4XeO6(aq) + 2H+(aq) + 2e- ![Examine the following half-reactions and select the strongest oxidizing agent among the substances. [PtCl<sub>4</sub>]<sup>2-</sup>(aq) + 2e<sup>-</sup> Pt(s) + 4Cl<sup>-</sup>(aq) ;E° = 0.755 V RuO<sub>4</sub>(s) + 8H<sup>+</sup>(aq) + 8e<sup>-</sup> Ru(s) + 4H<sub>2</sub>O(l) ;E° = 1.038 V FeO<sub>4</sub><sup>2-</sup>(aq) + 8H<sup>+</sup>(aq) + 3e<sup>-</sup> Fe<sup>3+</sup>(aq) + 4H<sub>2</sub>O(l) ;E° = 2.07 V H<sub>4</sub>XeO<sub>6</sub>(aq) + 2H<sup>+</sup>(aq) + 2e<sup>-</sup> XeO<sub>3</sub>(aq) + 3H<sub>2</sub>O(l) ;E° = 2.42 V A) [PtCl<sub>4</sub>]<sup>2-</sup>(aq) B) RuO<sub>4</sub>(s) C) HFeO<sub>4</sub><sup>-</sup> (aq) D) H<sub>4</sub>XeO<sub>6</sub>(aq) E) Cl<sup>-</sup>(aq)](https://d2lvgg3v3hfg70.cloudfront.net/TB5832/11ea8a63_0609_ead7_9a87_cd901242f4cd_TB5832_11.jpg)
XeO3(aq) + 3H2O(l) ;E° = 2.42 V
A) [PtCl4]2-(aq)
B) RuO4(s)
C) HFeO4- (aq)
D) H4XeO6(aq)
E) Cl-(aq)
Correct Answer:
Verified
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